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July 31, 2014

July 31, 2014

Posted by **fishbowl** on Saturday, August 9, 2008 at 11:33am.

2log(4)9-log(2)3

*(base)

i know the answer is log(2)3 but i can't figure out the work to get that answer

- Math -
**drwls**, Saturday, August 9, 2008 at 1:30pmUse the rules for changing the base of a logarithm at

http://oakroadsystems.com/math/loglaws.htm#NewBase

It says that

log(a)x = log(b)x/log(b)a

In your case, use it to show that

log(4)9 = log(2)3^2/log(2)4

= 2log(2)3/log(2)4 = log(2)3 !!

Therefore 2log(4)9 = 2 log(2)3

Subtracting 2log(2)3 from that leaves you with log(2)3

- Math (correction) -
**drwls**, Saturday, August 9, 2008 at 1:32pmThe last line should read:

Subtracting log(2)3 from 2log(2)3 leaves you with log(2)3

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