Posted by crystal on Friday, August 8, 2008 at 7:58pm.
Convert 2.13 g TlOH to moles. Divide moles by 1 liter to get the molar concentration in moles/liter or "M".
moles/L of TlOH = moles/L of OH- ions (since TlOH is a strong base). Calculate the pOH:
pOH = -log[OH-]
and
pH = 14 - pOH
i did this problem with 2.48 g and got 1.42 pH for OH- and 12.6 for H+
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