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August 2, 2014

Homework Help: ap chem

Posted by ted on Friday, August 8, 2008 at 3:51pm.

i am stuck on this problem from school

A solution is made by mixing 30.0 mL of toluene C6H5CH3d=0.867gmL with 130.0 mL of benzene C6H6d=0.874gmL . Assuming that the volumes add upon mixing, the molarity (M) and molality (m) of the toluene are

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