algebra
posted by Dede .
A rectangular swimming pool is twice as long as it is wide. A small walkway surrounds the pool. The walkway is a constant 2 feet wide and has an area of 196 square feet. Find the dimensions of the pool.: *

call the width w
then the length is 2w
then the total width including the walkway on each side is (w+4)
and the length including the walkway on each end is
(2w+4)
We are told that the total area including the walkway minus the area of the pool itself is 196 ft^2
so
(2w+4)(w+4)  2w^2 = 196
2 w^2 + 12 w + 16  2 w^2 = 196
You can take it from there I think
I get 15 by 30