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March 28, 2015

March 28, 2015

Posted by **Dede** on Friday, August 8, 2008 at 2:50pm.

- algebra -
**Damon**, Friday, August 8, 2008 at 3:11pmcall the width w

then the length is 2w

then the total width including the walkway on each side is (w+4)

and the length including the walkway on each end is

(2w+4)

We are told that the total area including the walkway minus the area of the pool itself is 196 ft^2

so

(2w+4)(w+4) - 2w^2 = 196

2 w^2 + 12 w + 16 - 2 w^2 = 196

You can take it from there I think

I get 15 by 30

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