Posted by fishbowl on Friday, August 8, 2008 at 12:12am.
Find the equation for the following circle:
The circle that passes through the origin and has intercepts equal to 1 and 2 on the x and yaxes, respectively.

Math  drwls, Friday, August 8, 2008 at 7:33am
That means it must pass though (0,0), (1,0) and (0,2) . The center must be located where the perpendicular bisectors of chords between those points intersect. That would be the point where the vertical line y = 1 and the horizontal ine x= 1/2 intersect, They cross at (1/2, 1) The radius is the distance of that point from any of the three given point, which is
R = sqrt[(1/2)^2 + 1^2] = sqrt (5/4)
Thus the circle equation is
(x0.5)^2 + (y1)^2 = 5/4
Check my thinking

Math  Adebimpe, Monday, February 8, 2016 at 3:06pm
y=53
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