Saturday

January 31, 2015

January 31, 2015

Posted by **fishbowl** on Friday, August 8, 2008 at 12:12am.

The circle that passes through the origin and has intercepts equal to 1 and 2 on the x- and y-axes, respectively.

- Math -
**drwls**, Friday, August 8, 2008 at 7:33amThat means it must pass though (0,0), (1,0) and (0,2) . The center must be located where the perpendicular bisectors of chords between those points intersect. That would be the point where the vertical line y = 1 and the horizontal ine x= 1/2 intersect, They cross at (1/2, 1) The radius is the distance of that point from any of the three given point, which is

R = sqrt[(1/2)^2 + 1^2] = sqrt (5/4)

Thus the circle equation is

(x-0.5)^2 + (y-1)^2 = 5/4

Check my thinking

**Answer this Question**

**Related Questions**

calculus - how would you find an equation for a circle that passes through the ...

mathematics - The circle x2-2x+y2-4y-4=0 lies on the cartesian plane,question 2....

math - can u help this the qustion is : A circle passes through the points (1,4...

maths - 1) Circle centre (7,-2) passes through (-2,10). Calculate radius and ...

mathematics - The circle x2-2x+y2-4y-4=0 lies on the cartesian plane,question 2....

mathematics - The circle x2-2x+y2-4y-4=0 lies on the cartesian plane,question 2....

mathematics - The circle x2-2x+y2-4y-4=0 lies on the cartesian plane,question 2....

steev - can u help this the qustion is : A circle passes through the points (1,4...

Geometry - Within an orthonormal system consider points A(1,4) B(5,1) C(4,8) (a)...

Math - Hi guys, In the question "It is given that P (0, 3), Q(7, 5), R(9, -2) ...