Wednesday
April 16, 2014

Homework Help: Math

Posted by David on Thursday, August 7, 2008 at 7:51pm.

No,
I'm sure the problem is written like this:
[(3a^3-27a)/(2a^2+13a-7)]/[9a^2/4a^2-1)]

And to divide you multiply by the reciprocal.

So i still don't get the problem I also know to factor, but I'm stil confused.

Answer this Question

First Name:
School Subject:
Answer:

Related Questions

Math - I'm totally stuck on this problem!! Simplify: (2a^2+13a-7/3a^3-27a)(4a^2-...
Mathematics - Hello, I am new to this website. I havea summer assignment on ...
Math - In this problem: -2/a+2 + 3a/2a-1 First I made the denominators alike: -2...
?? - 2a-3 x a+2 --------------- 4a-6 <-ok why does 4a plus 2a^2-3a <3b = ...
maths algebra - 3a-2(2a+4) 3a-2(2a + 4) you multiply the parenthesis by -2, ...
math - my topic is all about sums and differences of a rational algebraic ...
algebra - 3(a+2)=4a I multiply 3*a+3*2=4a so 3a+6=4a I added 3a to 4a/ =7a and ...
Algebra - multipy & simplify 2a^2 b^3 x 4a^-3 b^-2 ---------- ------------ 2ab^...
More Math 2 See If You Can Help Me... :) - Problem: a^2-9 a^2-3a...
math - 6a^2+4a+5+3a^2+7a-2 That is the same thing as 9a^2+11a+3, but what is the...

Search
Members