Posted by David on Thursday, August 7, 2008 at 7:15pm.
I'm totally stuck on this problem!!
Simplify:
(2a^2+13a7/3a^327a)(4a^21/9a^2)

Math  drwls, Thursday, August 7, 2008 at 7:36pm
This probably should have been written as
(2a^2+13a7)/[(3a^327a)(4a^21)/9a^2]
Try factoring 2a^2 +13a 7 into
(2a 1)(a+7)
and 3a^327a into
3a(a^29 = 3a(a+3)(a3)
and 4a^2 1 into (2a +1) (2a 1)
The 3a and (2a1) terms will cancel.

Math  David, Thursday, August 7, 2008 at 7:49pm
No,
I'm sure the problem is written like this:
[(3a^327a)/(2a^2+13a7)]/[9a^2/4a^21)]
And to divide you multiply by the reciprocal.
So i still don't get the problem I also know to factor, but I'm stil confused.

Math  bobpursley, Thursday, August 7, 2008 at 7:53pm
What you just typed as sure as the problem as written is NOT close to what you posted. Factor, then divide out common factors.
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