I know i'm a slow bunny and the answer is in my face but please help!
(4p-1)(16p^2+4p+1)
Multiply (16p^2+4p+1) by 4p, and then subtract (16p^2+4p+1) from what you get.
64p^3 + 16 p^2 + 4p - 16p^2 -4p -1
= 64 p^3 -1.
sorry man I still don get it. I have to find the product. I don't know where you got the 64^3 from. Can you please take me step by step
There was no 64^3 in my anser.
64p^3 is the product of the 16 p^2 and 4p terms. I suggest you review the distributive propery of algebra:
a (b +c) = ab + ac
ok thanks
To find the product of the given expression, (4p-1)(16p^2+4p+1), we can use the distributive property of multiplication over addition or subtraction.
We can distribute the first term (4p) of the first expression to every term of the second expression and then distribute the last term (-1) of the first expression to every term of the second expression.
Let's break it down step by step:
Step 1: Distribute 4p to every term in the second expression.
(4p)(16p^2) + (4p)(4p) + (4p)(1)
Simplifying this, we get:
64p^3 + 16p^2 + 4p
Step 2: Distribute -1 to every term in the second expression.
(-1)(16p^2) + (-1)(4p) + (-1)(1)
Simplifying this, we get:
-16p^2 - 4p - 1
Now, we combine the two results from step 1 and step 2:
(4p-1)(16p^2+4p+1) = 64p^3 + 16p^2 + 4p - 16p^2 - 4p - 1
Simplifying this further, we get:
64p^3 - 1
Therefore, the expansion of the given expression is 64p^3 - 1.