Posted by **Nahel** on Wednesday, August 6, 2008 at 9:15pm.

Hooke's Law asserts that the force required to either stretch or compress a spring from its natural length varies as the displacement. A certain spring is stretched 12 inches beyond its natural length by a 3 lb. weight. Express the force in terms of the displacement for this spring.

- Sorry, another math problem please -
**bobpursley**, Wednesday, August 6, 2008 at 9:34pm
force in term of dispacement?

3lb/12in or 1lb/4inches

- Sorry, another math problem please -
**Nahel**, Wednesday, August 6, 2008 at 9:37pm
Oh really? Is that all was meant? Perhaps I was thinking along too complex lines.

Thanks, I appreciate it.

- Sorry, another math problem please -
**Dr Russ**, Thursday, August 7, 2008 at 6:10am
Probably 4oz/inch iz best.

## Answer This Question

## Related Questions

- Math - Hooke's Law states that the distance a spring will stretch beyond its ...
- Pre-calculus - Hooke's Law states that the distance a spring will stretch beyond...
- work force - a force of 10 pounds is required to stretch a spring of 4 inches ...
- calculus - a spring exerts a force of 150 N when it is stretched 0.4 m beyond ...
- Math-Hooke's law - Using Hooke's Law (F=kx) determine: A) A weight of 5 pounds ...
- Calculus/Physics - A spring has a natural length of 10in. An 800lb force ...
- Calculus 2 - Suppose that a spring has a natural length of 25 cm, and ...
- Pre-Calculus - The amount of force required to compress a spring is inversely ...
- Calculus - A force of 6 pounds is required to hold a spring stretched 0.2 feet ...
- math - A spring with a mass of 4 kg has damping constant 28, and a force of 12 N...

More Related Questions