Posted by Elisa on Wednesday, August 6, 2008 at 12:06am.
The pendulum will act as if the gravitational acceleration were the vector sum of g (down) and -a, aimed 15 degrees below horizontal. Call the resultant g'
g' = sqrt (g^2 + a^2 - 2 ag cos 105) = 10.96 m/s^2
Then use g' instead of g in the formula for the period.
P = 2 pi sqrt (L/g')
Just adding the vertical component of a to g will not get you the right answer for g'.
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