Posted by **Nahel** on Tuesday, August 5, 2008 at 8:59pm.

A rectangular lot is to be bounded by a fence on three sides and by a wall on the fourth side. Two kinds of fencing will be used with heavy duty fencing selling for $4 a foot on the side opposite the wall. The two remaining sides will use standard fencing selling for $3 a foot. What are the dimensions of the rectangular plot of greatest area that can be fenced in at a cost of $6600?

THANK YOU!!!

- word problem? -
**Damon**, Tuesday, August 5, 2008 at 9:19pm
cost = 6 b + 4 L = 6600

area = b L

so

4 L = 6600 - 6 b

L = 1650 - 1.5 b

area = y = 1650 b - 1.5 b^2

that is a parabola opening down, the maximum will be at the vertex

find the vertex

1.5 x^2 -1650 x = -y

x^2 - 1100 x = -2 y/3

x^2 - 1100 x + 302500 = -2 y/3 + 302500

(x-550)^2 = -2 y/3 + 302500

x = b = 550

so L = 1650 - 1.5 (550)

L = 825

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