Posted by kayla on Tuesday, August 5, 2008 at 2:55pm.
A 0.500M solution of a weak acid, HX, is only partially ionized. The [H+] was found to be 4.02 x 10^3 M. Find the dissociation constant for this acid.

chemistry  DrBob222, Tuesday, August 5, 2008 at 3:34pm
HX ==> H^+ + X^
Ka = (H^+)(X^)/(HX)
Set up an ICE chart, substitute for each component in the Ka expression and solve for Ka. I get 3.26 x 10^3. Don't forget to subtract 4.02 x10^3 from 0.500 M to obtain unionized (HX); i.e., it isn't 0.500, it is 0.500  0.00402.