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September 18, 2014

September 18, 2014

Posted by **Chan** on Monday, August 4, 2008 at 11:25am.

y=squareroot of x^3-3x^2 ?

- calculus -
**drwls**, Monday, August 4, 2008 at 1:26pmI will assume that you meant to write

y = squareroot of (x^3-3x^2) and not

y = (squareroot of x^3) - 3x^2

Since you cannot take the square root of a negative number (unless you are dealing with imaginary numbers), the domain is wherever x^3 > 3x^2. Since x^2 is always positive, you can divide both sides by x^2 and keep the > sign in the same direction. This leaves you with x > 3

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