Thursday

August 21, 2014

August 21, 2014

Posted by **Chan** on Monday, August 4, 2008 at 11:25am.

y=squareroot of x^3-3x^2 ?

- calculus -
**drwls**, Monday, August 4, 2008 at 1:26pmI will assume that you meant to write

y = squareroot of (x^3-3x^2) and not

y = (squareroot of x^3) - 3x^2

Since you cannot take the square root of a negative number (unless you are dealing with imaginary numbers), the domain is wherever x^3 > 3x^2. Since x^2 is always positive, you can divide both sides by x^2 and keep the > sign in the same direction. This leaves you with x > 3

**Related Questions**

Algebra - I need some help figuring these. Compute each product and simplify ...

Algebra - I need some help figuring these. Compute each product and simplify the...

calculus - write the expression in the form bi, where b is the real number ...

math/calculus - f(x)=the squareroot of (x^2-9) and g(x)=1/x-4 find the domain ...

calculus - find the area of the region enclosed by y=squareroot of x, the line ...

Algebra2 - Simplify: 1.SquareRoot(-144) 2.SquareRoot(-64x^4) 3.SquareRoot(-13)*...

math - Classify each statement as sometimes, always, or never true. A. 2^(2/3)*4...

algebra - ^5 squareroot of x^20 *my answer x^4 ^3 squareroot of 729/343 my ...

math 11 review - A couple of extra practice questions I can't remember how to do...

Math - For the function g(x)=squareroot(2x+3), find the domain and rage of g.