Posted by **Sunflower** on Sunday, August 3, 2008 at 11:36pm.

(x^4y^6z^12/9^-2x^3y^-8z^-9)^0

- Algebra -
**drwls**, Monday, August 4, 2008 at 12:03am
Is the ^ supposed to represent that what follows is an exponent? You have exponents added on top of exponents.

Since the whole thing is raised to the zero power, the result is 1, no matter what x, y and z are.

A trick question, perhaps.

- Algebra -
**Sunflower**, Monday, August 4, 2008 at 12:05am
This is what the professor gave use to do. Is there anyway you can so me how you got 1?

- Algebra -
**drwls**, Monday, August 4, 2008 at 12:08am
Any number to the zero power is 1.

Why? Because for ANY number N

N / N = 1 = N^1 * N*-1 = N^0

- Algebra -
**Sunflower**, Monday, August 4, 2008 at 12:11am
thanks

- Algebra -
**DrBob222**, Monday, August 4, 2008 at 12:14am
Any number raised to the zero power is 1.

50,000^0 = 1.

6,245^0 = 1

Try seeing it this way.

X^3*X^-3 = X^{3-3} = X^{0} but

X^3*X^-3 = X^3/X3 = 1; therefore, it follows that X^{0} = 1

- Algebra -
**drwls**, Monday, August 4, 2008 at 9:24am
"question 1" looks like two questions. The first one needs more parentheses to explain the order of operations. The second one cannot be solved becasue it contains two variables.

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