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Algebra II/Trig

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Simplify:
1/5(-5a^2b^3)^2(abc)^4

How do you simplify this.

How does the "-5" play a role in this?
how would you get 1/5 of "-5"

  • Algebra II/Trig -

    1/5(-5a^2b^3)^2(abc)^4

    = 1/5[(-5)^2(a^2)^2(b^3)^2][(a^4)(b^4)(c^4)]
    = 1/5[25a^8b^10c^4]
    = 5(a^8)(b^10)(c^4)

    1/5 of "-5" would be -1 but you have to do the powers (exponents) before you do the division or multiplication

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