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February 28, 2015

February 28, 2015

Posted by **Alex** on Sunday, July 27, 2008 at 7:57am.

- alberbra -
**Reiny**, Sunday, July 27, 2008 at 9:25amfirst of all, find the number of days in 4 years, which would be 3x365 + 366 (one leap year)

the days that a law can be passed has to be divisible by 10, 12 and 7

the lowest common multiple would be 420

How many multiples of 420 are there in your total number of days?

- alberbra -
**Alex**, Sunday, July 27, 2008 at 6:49pm3, thanx

- alberbra -
- alberbra -
**drwls**, Sunday, July 27, 2008 at 9:31amThe number of days after January 1, 1996 must be divisible by 10, 12 and 7. It must also be less than 365x4 = 1460.

The Lowest Common Multiple of those numbers is 2^2*3*5*7 = 420 (i.e, they can pass a law every 60 weeks.)The number of opportunitites is the integer part of 1460/420, which is three.

- alberbra -
**Alex**, Sunday, July 27, 2008 at 7:11pmthank-you very much

- alberbra -

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