Posted by **jess** on Friday, July 25, 2008 at 9:56am.

John is three times as old as his son, Michael, and in x year time he will be twice as old as him

(i) write down expressions for Johns and Michaels age in x years time

(ii) write down and solve an equation in x

I know the answers as they are in the back of my book although I don't understand WHY that is, so please can someone explain it to me? Thank you so much in advance!

- math -
**Damon**, Friday, July 25, 2008 at 10:15am
call Michael's age m

then John's age is 3 m

in x years, Michael will be (m + x) years old

in x years, John's age will be 3 m + x

The problem statement says that

3 m + x = 2 (m + x)

3 m + x = 2 m + 2 x

x = m

for example if today Michael is 10 and John is 30

then x = m = 10

and in 10 years

Michael is 20

and John is 40

and sure enough 40 is twice 20

- math -
**drwls**, Friday, July 25, 2008 at 10:27am
You are supposed to write down two equations and solve them to obtain rhe age of John (J) and of Michael (M).

Let John's age now be J. Let Michael's age now be M. In x years, John's age will be

J' = J + x

and Michael's age will be

M' = M + x

If J'/M' = 2, then

(J+x)/M+x) = 2

J +x = 2M + 2x

You also know that J = 3M, so

3M + x = 2M + 2x

M = x

No matter what John's age is now, there is an x value that satisfies the two requirements. That is because you have only two equations in three unknowns.

- math -
**tchrwill**, Friday, July 25, 2008 at 10:32am
1--J = 3S

2-- J + X = 2(S + X)

3--3S + x = 2S + 2x

4--S = x

5--J = 3x

6--Select an x and solve for J and S

7--x........10...15...20...25...etc.

...S........10...15...20...25...etc.

...J........30...45...60...75...etc.

.S+x........20...30...40...50...etc.

.J+x........40...60...80..100...etc.

(J+x)/(S+x)..2....2....2....2

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