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April 21, 2014

April 21, 2014

Posted by **raven** on Thursday, July 24, 2008 at 11:20pm.

- algebra and trigonometry -
**drwls**, Friday, July 25, 2008 at 1:11amLet the diagonal be c and the sides a and b

b = sqrt (c^2 - a^2) = sqrt(25-a^2)

Perimeter = 2a + 2b = 2a + 2sqrt (25-a^2) = 14

14 - 2a = 2 sqrt (25-a^2)

196 - 56a + 4a^2 = 4(25-a^2) = 100 -4a^2

8a^2 -56a +96 = 0

a^2 -7a + 12 = 0

(a-3)(a-4) = 0

The side lengths are 3 and 4

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