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CALCULUS

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A PIECE OF SHEET METAL IS 2.6 TIMES AS LONGS AS IT IS WIDE.
IT IS TO BE MADE INTO A BOX WITH AN OPEN TOP BY CUTTING 3-INCH SQUARES FROM EACH CORNER AND FOLDING UP THE SIDES.

IF THE VOLUME OF THE BOX MUST BE BETWEEN 600 AND 800 CUBIC INCHES, WHAT VALUES OF X WILL PRODUCE THIS RANGE OF VOLUMES?

  • CALCULUS - ,

    width of sheet = x ??? I will assume

    b, breadth of box = x - 6
    L = length of box = 2.6 x - 6
    height = 3
    600 ≤ 3(x-6)(2.6 x - 6) ≤ 800

    600 ≤ 7.8 x^2 -64.8 x + 108 ≤ 800

    492 ≤ 7.8 x^2 - 64.8 x ≤ 692
    solve those quadratics (ignore negative solutions)
    x = 13.1
    x = 14.4

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