Posted by **Andrea** on Thursday, July 24, 2008 at 7:15pm.

A car manufacturing company (the Company) can produce a car for $3000.00 and a truck for $5000.00. Suppose "C" cars and "T" trucks are sold to the dealer at mark-ups, respectively, of 20 and 30 percent. If the Company made a profit of $27 million on sales of $137 million in one particular year, how many cars and trucks were sold by the company in that year?

I have to get 2 equations from this and use the substitution or elimination method

- Pre-Calculus -
**drwls**, Thursday, July 24, 2008 at 7:22pm
The first equation would be

3000 C + 5000 T = 137,000,000 (total sales)

The second equation would be

3000*.20*C + 5000*.30*T = 27,000,000 (profit)

This can be rewritten

600 C + 1500 T = 27,000,000

Now solve those two equations for C and T, the number of cars and trucks sold, using either method.

- Pre-Calculus -
**drwls**, Thursday, July 24, 2008 at 10:03pm
I get the same result as you, and checked my work. I have no explanation

- Pre-Calculus -
**Brandon**, Saturday, July 26, 2008 at 8:05pm
Sometimes one winds up with an "erroneous" solution.

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