3Cu+8HNO3--> 3Cu(NO3)2+ 2NO+4H2O

How many moles of HNO3 are required to react with 6 moles of Cu?

How many moles of Cu(NO3)2 are produced when 3 moles of Cu react?

How many moles of Cu must react to produce 4 moles of NO?

If 4 moles of NO are produced, how many moles of H2O are also produced?

How to go about solving these questions? Please help.

It's all done with the balanced equation and the coefficients. Here is an example. Note how the FACTOR converts from one material to the other.

mols NO = 4. We want to convert to mols Cu.
mols Cu = mols NO x (factor)
factor is 3 mols Cu/2mols NO. So
mols Cu = 4 mols NO x (3 mols Cu/2 mols NO) = 4 x 3/2 = 12/2 = 6
You COULD have written the factor as the reciprocal; i.e., 2 mols NO/3 mols Cu BUT note that the units would not cancel if you did that. So the factor ALWAYS is used so that the unit we don't want cancels and the unit we want the answer to be in is left. Post your answers to the others and someone shall be happy to check them.

no help my dude

To solve these questions, we need to use the balanced chemical equation provided:

3Cu + 8HNO3 → 3Cu(NO3)2 + 2NO + 4H2O

1. How many moles of HNO3 are required to react with 6 moles of Cu?
From the balanced equation, we can see that the stoichiometric ratio between Cu and HNO3 is 3:8. Therefore, for every 3 moles of Cu, we need 8 moles of HNO3.
So, if we have 6 moles of Cu, we can use the stoichiometry to calculate the corresponding amount of HNO3:
(6 moles Cu) × (8 moles HNO3 / 3 moles Cu) = 16 moles HNO3

Therefore, you would need 16 moles of HNO3 to react with 6 moles of Cu.

2. How many moles of Cu(NO3)2 are produced when 3 moles of Cu react?
From the balanced equation, we can see that the stoichiometric ratio between Cu and Cu(NO3)2 is 3:3. Therefore, for every 3 moles of Cu, we will produce 3 moles of Cu(NO3)2.
So, if we have 3 moles of Cu, we can use the stoichiometry to calculate the corresponding amount of Cu(NO3)2:
(3 moles Cu) × (3 moles Cu(NO3)2 / 3 moles Cu) = 3 moles Cu(NO3)2

Therefore, 3 moles of Cu(NO3)2 are produced when 3 moles of Cu react.

3. How many moles of Cu must react to produce 4 moles of NO?
From the balanced equation, we can see that the stoichiometric ratio between Cu and NO is 3:2. Therefore, for every 3 moles of Cu, we will produce 2 moles of NO.
So, if we have 2 moles of NO, we can use the stoichiometry to calculate the corresponding amount of Cu:
(2 moles NO) × (3 moles Cu / 2 moles NO) = 3 moles Cu

Therefore, 3 moles of Cu must react to produce 4 moles of NO.

4. If 4 moles of NO are produced, how many moles of H2O are also produced?
From the balanced equation, we can see that the stoichiometric ratio between NO and H2O is 2:4. Therefore, for every 2 moles of NO, we will produce 4 moles of H2O.
So, if we have 4 moles of NO, we can use the stoichiometry to calculate the corresponding amount of H2O:
(4 moles NO) × (4 moles H2O / 2 moles NO) = 8 moles H2O

Therefore, if 4 moles of NO are produced, 8 moles of H2O are also produced.

I hope that helps! Let me know if you have any further questions.

To solve these questions, we need to use the balanced chemical equation provided, which is:

3Cu + 8HNO3 → 3Cu(NO3)2 + 2NO + 4H2O

1. How many moles of HNO3 are required to react with 6 moles of Cu?
Based on the equation, we have a 3:8 ratio between Cu and HNO3. Therefore, we can set up a proportion:

(6 moles Cu) / (1 mole Cu) = (x moles HNO3) / (8 moles HNO3)

Cross-multiplying, we find:
6 moles Cu * 8 moles HNO3 = 1 mole Cu * x moles HNO3
48 moles HNO3 = x moles HNO3

So, 48 moles of HNO3 are required to react with 6 moles of Cu.

2. How many moles of Cu(NO3)2 are produced when 3 moles of Cu react?
Using the equation, we have a 3:3 ratio between Cu and Cu(NO3)2:

(3 moles Cu) / (1 mole Cu) = (x moles Cu(NO3)2) / (1 mole Cu(NO3)2)

Cross-multiplying, we find:
3 moles Cu * 1 mole Cu(NO3)2 = 1 mole Cu * x moles Cu(NO3)2
3 moles Cu(NO3)2 = x moles Cu(NO3)2

So, 3 moles of Cu(NO3)2 are produced when 3 moles of Cu react.

3. How many moles of Cu must react to produce 4 moles of NO?
From the equation, we have a 2:3 ratio between NO and Cu:

(4 moles NO) / (1 mole NO) = (x moles Cu) / (3 moles Cu)

Cross-multiplying, we find:
4 moles NO * 3 moles Cu = 1 mole NO * x moles Cu
12 moles Cu = x moles Cu

So, 12 moles of Cu must react to produce 4 moles of NO.

4. If 4 moles of NO are produced, how many moles of H2O are also produced?
Based on the equation, we have a 2:4 ratio between NO and H2O:

(4 moles NO) / (1 mole NO) = (x moles H2O) / (4 moles H2O)

Cross-multiplying, we find:
4 moles NO * 4 moles H2O = 1 mole NO * x moles H2O
16 moles H2O = x moles H2O

So, if 4 moles of NO are produced, 16 moles of H2O are also produced.

By setting up and solving these proportions, you can find the required moles of each substance involved in the chemical reaction.