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September 15, 2014

September 15, 2014

Posted by **Veronica** on Wednesday, July 23, 2008 at 8:10pm.

Using the chain rule...I figured out my previous post.

- Calculus -
**drwls**, Thursday, July 24, 2008 at 12:09amh(x) = 7x *(5-2x)^-1/2

dh/dx = 7 (5-2x)^-1/2

+ (7x)d/dx(5-2x)^-1/2

Use the chain rule on the second term

d/dx(5-2x)^-1/2 = (-1/2)(-2)(5-2x)^-3/2

= (5-2x)^-3/2

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