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An object weighing 340 N in air is immersed in water after being tied to a string connected to a balance. The scale now reads 260 N. Immersed in oil, the object weighs 290 N.

(a) Find the density of the object.
(b) Find the density of the oil.

  • Physics -

    The volume of water displaced weighs 80 N, and has a mass of 80 N/g = 8.16 kg. That amount of water occupies 8.16 liters, or 8.16*10^-3 m^3, and equals the volume of the object. So the object's density is
    [340 N/g]/8.16*10^-3 m^3
    = 4250 kg/m^3

    The weight reduction in oil is 5/8 of the weight reduction in water, so the oil has 50/80 of the density of water, or 625kg/m^3

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