Wednesday

July 23, 2014

July 23, 2014

Posted by **Rachel** on Tuesday, July 22, 2008 at 9:56pm.

- Help with Math -
**Dr Russ**, Wednesday, July 23, 2008 at 7:31amThis is similar ot the other problem.

If the equation crosses the x-axis then y=0.

So you need to find the solutions for

0=2x^2-2x+3k

using the general equation we get

x=-2+/-(4-4.2.3k)^.5/4

for there to be real values

4-24k>0 (we can't square root a number less than zero, and it can't equal zero as the question says there are two distinct points. Zero would give us two coincident points)

so 4>24k or k<4/24 k<0.1667

Check my working!

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