How would i solve x^3-3x^2+2=0?
How would i show it in exact values?
Note that one root is x=1. Call it a lucky guess.
That means that (x-1) is a factor of x^3-3x^2+2.
Use long division to get the other factor: x^2 -2x -2
That factors into (x - 1 -sqrt3) and (x - 1 + sqrt3)
That should tell you all three roots:
1, 1 + sqrt 3 and 1 - sqrt 3