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September 2, 2014

September 2, 2014

Posted by **Rachel** on Tuesday, July 22, 2008 at 9:28pm.

How would i show it in exact values?

- Function -
**drwls**, Tuesday, July 22, 2008 at 11:06pmNote that one root is x=1. Call it a lucky guess.

That means that (x-1) is a factor of x^3-3x^2+2.

Use long division to get the other factor: x^2 -2x -2

That factors into (x - 1 -sqrt3) and (x - 1 + sqrt3)

That should tell you all three roots:

1, 1 + sqrt 3 and 1 - sqrt 3

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