physics

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Determine the elongation of the rod in if it is under a tension of 5.7E10^3 N.

The rod is made of aluminum and copper. From the aluminum to the copper section it measures 1.3m and from the copper section to the end it measures 2.6m with a radius of 0.2cm.

• physics - ,

Add the elongations of the aluminum and copper sections. The elongation of each is

delta L = L * T/(AY)

Where L is the length of that material, A is the cross sectional area and Y is Young's modulus, which you will have to look up.

For copper:
L = 2.6 m
A = (pi)*(2*10^-3 m)^2
Your text should have Young's modulus values for aluminum and copper; otherwise try googling it.

• physics - ,

You can find Young's modulus values for many materials, including copper and aluminum, at
http://en.wikipedia.org/wiki/Young's_modulus
It is represented by the symbol E there, not Y.
For copper is it about 120* 10^9 N/m^2 .
They use the units of GigaPascals (GPa), which is 10^9 N/m^2.

• physics - ,

Thank you very much!