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Posted by on Monday, July 21, 2008 at 10:22pm.

WHAT IS THE MOLARITY OF A SOLUTION PREPARED BY DISSLOVING 4.92 GRAMS OF CALCIUM NITRATE, Ca(NO3)2 in 250 mL OF WATER?

  • CHEMISTY - , Monday, July 21, 2008 at 10:28pm

    Remember the definition.
    M = #mols/L.
    # mols = grams/molar mass.
    Post your work if you get stuck.

  • CHEMISTY - , Monday, July 21, 2008 at 10:36pm

    Dr. Bob222 I'm not following. Would you please further explain?

    Thanks

  • CHEMISTY - , Monday, July 21, 2008 at 10:52pm

    Plug in the numbers.
    # mols = g/molar mass = 4.92/molar mass Ca(NO3)2 = xx mols Ca(NO3)2.

    Then M = #mols/L = xxmols/0.250 L = ?? M.

  • CHEMISTY - , Monday, July 21, 2008 at 10:55pm

    Technically, the problem should have said in 250 mL of SOLUTION. There is a difference. Or the problem could have said dissolve in a little water and make to a final volume of 250 mL. Or they could have asked for the molality and given the density and calculated the molarity that way; however, I think, in the spirit of the problem that it means 250 mL solution.

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