Posted by ruby on Monday, July 21, 2008 at 7:21pm.
It travels upwards until the vertical velocity component becomes zero. An easier way to calculate it it to require that the initial kinetic energy become completely potential energy there.
(1/2) M Vo^2 = M g H
where H is the maximum height above the thrower's hand.
H = Vo^2/(2 g) = 11.5 m
The time in the air is twice the time it takes for the velocity upward to become zero. It spends an equal length of time coming back down. Therefore:
T = 2 * (Vo/g) = 3.06 s
thanx so much! im finally starting to get this!
Related Questions
physics - a person throws a ball upward into the air with an initial velocity of...
Physics - A person throws a ball upward into the air with an initial velocity of...
Physics - A person throws a ball upward into the air with an initial velocity of...
physics - a person throws a ball upward into the air with an initial velocity of...
Physics - Units count. Show all steps, not just the numerical substitutions. ...
Physics - Units count. Show all steps, not just the numerical substitutions. ...
Physics - Two students are on a balcony 19.6 m above the street. One student ...
physics - A person throws a 2.5 lb stone into the air with an initial upward ...
Physics - Two students are on a balcony 24.3 m above the street. One student ...
physics - two students are on a balcony 20.6 m above the street. One student ...
For Further Reading
