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October 2, 2014

October 2, 2014

Posted by **Izzy** on Monday, July 21, 2008 at 1:54pm.

- Algebra -
**Damon**, Monday, July 21, 2008 at 2:01pmPlease be careful to type exactly what your question is. Could you possibly mean the equation

y = -4 x - 10 ????

in that case the slope would be - 4 and when x = 0 the line hits y = -10 so the y intercept is -10

- Algebra -
**Izzy**, Monday, July 21, 2008 at 2:54pmno the question is what is the slope and y-intercept of the line in part b? and part b gives the equation y=-2/3x-12

then tells you that they may want to make repairs could you place it at the point (-4,10)on the graph.

- Algebra -
**Damon**, Monday, July 21, 2008 at 9:38pmOh, ok sure if the equation is

y = -(2/3)x - 12

the slope is -2/3

when x = 0, y = -12 so -12 is the y intercept

when y = 0, x = -18 so that is the x intercept

now if the point (-4,10) is on the line then:

10 = -(2/3)(-4) - 12 ???

10 = 8/3 - 12 no way, not on the line

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