Posted by Izzy on Monday, July 21, 2008 at 1:41pm.
If you have the equation y=-1/2x-4
How would you set up a table for the equation for x, y (xy)?
- Algebra - Damon, Monday, July 21, 2008 at 1:57pm
Do you mean
a) y = [-1/(2x)] -4
b) y = -(1/2)x - 4
c) y = -1 / (2x-4)
- Algebra - Izzy, Monday, July 21, 2008 at 2:51pm
It is a table with x in the first box at the top y is in the second box and (xy) is the third box. Now under each varable you are supposed to complete the table using the equation. There are 5 rows down under each varable.
x y (xy)
Then solve for x, y and (x,y)
- Algebra - Damon, Monday, July 21, 2008 at 9:44pm
But I do not know what your equation is. Do you mean a, b, or c ?
if it is b then
y = -(1/2)x - 4 is the same as x = -2(y+4)
now if y = -1 is given
then x = -6
and xy = 6
if x = -2 is given
then y = -3
and xy = 6
if y = -4 is given
then x = 0
and xy = 0
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