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September 1, 2014

September 1, 2014

Posted by **Izzy** on Monday, July 21, 2008 at 1:41pm.

How would you set up a table for the equation for x, y (xy)?

- Algebra -
**Damon**, Monday, July 21, 2008 at 1:57pmDo you mean

a) y = [-1/(2x)] -4

or

b) y = -(1/2)x - 4

or

c) y = -1 / (2x-4)

????????????????????????

- Algebra -
**Izzy**, Monday, July 21, 2008 at 2:51pmIt is a table with x in the first box at the top y is in the second box and (xy) is the third box. Now under each varable you are supposed to complete the table using the equation. There are 5 rows down under each varable.

x y (xy)

______-1______________

-2____________________

______-4______________

2____________________

8____________________

Then solve for x, y and (x,y)

- Algebra -
**Damon**, Monday, July 21, 2008 at 9:44pmBut I do not know what your equation is. Do you mean a, b, or c ?

if it is b then

y = -(1/2)x - 4 is the same as x = -2(y+4)

now if y = -1 is given

then x = -6

and xy = 6

if x = -2 is given

then y = -3

and xy = 6

if y = -4 is given

then x = 0

and xy = 0

etc

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