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July 23, 2014

July 23, 2014

Posted by **Anonymous** on Monday, July 21, 2008 at 12:51pm.

Equation:

Answer:

- algebra -
**Reiny**, Monday, July 21, 2008 at 1:06pmlooks very similar to the question just posted by Lily.

let the amount of 30% solution we want to add be x l

now let's reason it through....

the volume of acid we have before adding is .3(10) l or 3 l

we are adding x l of a 20% solution so we are adding .2x l

but the final solution containing 10+x l is to contain 25% acid or .25(10+x) l of acid

so isn't our equation...

3 + .2x = .25(10+x) ?

solve for x and tell me what you got.

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