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October 1, 2014

October 1, 2014

Posted by **JO** on Sunday, July 20, 2008 at 1:15pm.

- algebra -
**Damon**, Sunday, July 20, 2008 at 1:19pm70 - 58 = 12 degrees in five hours

12/5 = 2.4 degrees per hour drop or -2.4 degrees per hour

- algebra -
**JO**, Sunday, July 20, 2008 at 6:54pmEvaluate. | –48 |

- algebra -
**Damon**, Sunday, July 20, 2008 at 7:04pm+48

- algebra -
**Jackie**, Wednesday, August 24, 2011 at 9:46pmDuring a six hour period, the temperture dropped 18degrees F. Find the average hourly change in the temperature.

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