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algebra

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Suppose the temperature outside is dropping at a constant rate. At noon , the temperature is 70 degrees f and it drops to 58 degrees f at 5:00 P.M. How much did the temperature change each hour?

  • algebra - ,

    70 - 58 = 12 degrees in five hours
    12/5 = 2.4 degrees per hour drop or -2.4 degrees per hour

  • algebra - ,

    Evaluate. | –48 |

  • algebra - ,

    +48

  • algebra - ,

    During a six hour period, the temperture dropped 18degrees F. Find the average hourly change in the temperature.

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