Sunday
March 26, 2017

Post a New Question

Posted by on .

Use Newton's method to approximate a root of the equation 5sin(x)=x as follows.
Let x1=2 be the initial approximation.
The second approximation x2 is:
and the third approximation x3 is:

  • Math - ,

    5 sin x = x
    let y = x - 5 sin x, search for y = 0
    dy/dx = y' = 1 - 5 cos x
    Xn+1 = Xn + y(Xn)/y'at Xn
    X1 = 2
    y = 2 - 5 sin 2 = 2 - 4.54 = -2.54
    y'=1 - 5 cos 2 = 3.08
    X2 = 2 -2.54/3.08 = 1.17

    y = 1.17 - 5 sin 1.17 = -3.43
    y' = 1 - 5 cos 1.17 = -.951
    X3 = 1.17 -3.43/-.951 = 4.77

    This is unlikely to work the way you want because you are jumping from cycle to cycle of the original sine wave

  • Math - ,

    The answers are wrong for this one.

  • Math - sign wrong - ,

    sorry, sign wrong. I drew my picture wrong
    5 sin x = x
    let y = x - 5 sin x, search for y = 0
    dy/dx = y' = 1 - 5 cos x
    Xn+1 = Xn - y(Xn)/y'at Xn
    X1 = 2
    y = 2 - 5 sin 2 = 2 - 4.54 = -2.54
    y'=1 - 5 cos 2 = 3.08
    X2 = 2 + 2.54/3.08 = 2.82

    y = 2.82 - 5 sin 2.82 = 1.24
    y' = 1 - 5 cos 2.82 = 5.74
    X3 = 2.82 -1.24/5.74 = 2.60

  • Math - sign wrong - ,

    The answer is still wrong :(

  • Math - ,

    check my arithmetic carefully

Answer This Question

First Name:
School Subject:
Answer:

Related Questions

More Related Questions

Post a New Question