if
n+5-n+3 over n-3-n-5=16
what is the value of n
this is an SAT question and i just cant seem to figure it out..even with pluggin in the numbers it never = 16...so help pls..what is the quickest way in solving this for the SAt's
The n's cancel out in the numerator AND denominator, and you are left with
8/(-8) = -1 = 16, which is of course not true, and cannot be solved for n. Are you sure you copied the problem correctly?
yeah n+5 should be over n-3 and n+3 should be over n-5 and your subtracting this frm eachother to equal 16
the possible answers are
-4
-2
2
4
6
If you mean
[(n+5)/(n-3)] - [(n+3)/(n-5)] = 16
First rewrite the left with a common denominator, (n-3)(n-5). You get
[(n^2-25) - (n^2-9)]/[(n-3)((n-5)]= 16
-16/[(n-3)(n-5)]= 16
(n-3)(n-5) = -1
n = 4
That is completely different from what you typed at first.
im soo sry...but that was it..thanxs soo much :)
To solve this equation for n, let's simplify the expression first:
(n + 5 - n + 3) / (n - 3 - n - 5) = 16
Begin by combining like terms within each set of parentheses:
(8) / (-8) = 16
Next, simplify the equation further by performing the arithmetic operations:
1 = 16
However, we can see that this equation is not true, which means there is no value of n that satisfies this equation.
In this case, it seems that there may have been a mistake in the original equation or it may have been written incorrectly. It's possible that something was misinterpreted or missed while reading the question.
When encountering a challenging question on the SAT or any other exam, it's essential to carefully review the question and the given information to ensure accuracy.