Thursday

November 20, 2014

November 20, 2014

Posted by **alk** on Friday, July 18, 2008 at 1:03pm.

how would i go about finding:

a) the center and the radius

b) the equation of the tangent line at the point (-2,5)

any help is mch appreciated. thanks!

- math -
**drwls**, Friday, July 18, 2008 at 3:20pm(a) Rewrite the equation as

x^2 + 6x + 9 + y^2 -4y + 4 +3 -13 = 0

(x+3)^2 + (y-2)^2 = 10 = (sqrt 10)^2

The should tell you that the center is at (-3, 2) and the circle radius is sqrt 10.

(b) First cmpute the slope dy/dx at (-2, 5)using implicit differentiation.

2x + 2y y' + 6 -4 y'= 0

y'(4 - 2y) = 2x + 6

y' = 2/(4-2y) = -1/3

Finally, write down the equation of s straight line passing through (-2,5) with that slope.

Verify my numbers. I may have goofed somewhere along the line

**Answer this Question**

**Related Questions**

calc - standard equation of circle concentric with X^2+Y^2-2X-8Y+1=0 and tangent...

Math (Pre Cal) - Hi, I am studying for a precalculus quiz and I do not ...

math - a circle is tangent to the y-axis at y=3 and has one x-intercept at x=1 a...

math - From an exteror point P that is h units form a circle of radius r, a ...

Math (geometry) - Line l is tangent to circle O at point P(3,4) where the center...

Math - I have a series of questions that I did. They lead up to the last ...

Math - I have a question my brother asked me but I need a math expert. You have ...

Alg2 - The tangent to a circle may be defined as the line that intersects the ...

GEOMETRY INSCRIBED ANGLES MULTIPLE CHOICE QUESTION - segment BC is tangent to ...

Geometry - I have a circle with a Tangent line, DE, running along it and ...