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September 16, 2014

September 16, 2014

Posted by **Proving Identities Question (Trig.)** on Friday, July 18, 2008 at 12:04pm.

a) (cosec θ + cotθ)(cosecθ - cotθ) = cotθtanθ

b) 2/(1 + sinθ) + 1/(1- sinθ) = (3sec^2)θ - tanθcosecθ

I basically just have to prove Left HandSide = Right Hand Side

- math -
**drwls**, Friday, July 18, 2008 at 1:06pm(a) You should immediately recognize that the right side equals 1. If you don't, then review the relationship of tan and cot.

Multiply out the two factors on the left and you get

csc^2 θ - cot^2 θ) = 1

Rewrite the left side as

1/ sin^2 - cos^2/sin^2 = 1

which is the same as

(1 - cos^2)/sin^2 = 1

1 = 1

For (b), I suggest first rewriting the left side with a common denominator. Also recognize that tan*csc on the right equals sec = 1/cos

- math -
**Anonymous**, Saturday, July 19, 2008 at 10:42amThanks drwls that really helped !

:)

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