CHEM
posted by JOE on .
Show that when pH = pKa, the maximum buffer capacity (at 298.15 K) is given by: âmax = 0.576C
where C is the total concentration of conjugate acid and conjugate base. The first two terms in the brackets on the right hand side of equation (8.5) can be neglected. B( KaCH/(Ka +H)^2 x ln 10

Have you posted everything in your problem? And what is a (with ^ over it) max?