algorithm
posted by alberto on .
can someone tell me if this is correct.
Write an algorithm that will display the sum for a given number of squares. In other words if the user enters the value 5, then the output should be 1^2 + 2^2 + 3^2 +4^2 + 5^2 = 55.
sumsquare integer
square integer
count integer
sumsquare := (y^2)
square := 1^2
count := 1
dowhile count = (x)
count = count + 1
sumsquare = sumquare + square
enddo
print\n "sumsquare is ", sumsquare

Your algorithm is probably OK, but where do you enter the value 5 for the number of terms?
This same problem popped up about 4 days ago, but not as a computer problem. It turns out that same series sum can be written
(1/3)n^3 + (1/2)n^2 + (1/6)n
Where n is the number of terms in the series. Try it!