Posted by Bryan on Thursday, July 17, 2008 at 8:57pm.
Start with the largest number -- 12
12, 24, 36, 48, 60, 72, 84, 96, 108, 120, 132, 144, 156, 168, 180 . . .
Which of the above numbers is evenly divisible by 3, 10, and 8?
120
3= 3
10 = 2*5
12 = 2*2*3
8 = 2*2*2
start with the longest string of prime factors : 2*2*2
now add on any other factors from the other strings that have not yet been put down
2*2*2*3*5 = 120