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September 1, 2014

September 1, 2014

Posted by **Frnciois** on Wednesday, July 16, 2008 at 10:06pm.

- algebra -
**drwls**, Wednesday, July 16, 2008 at 10:17pmStopping distance = C r^2

270 = C*70^2

C = 270/70^2

At 50 mph,

stopping distance = 50^2*270/(70^2)

= (5/7)^2 * 270 ft = ?

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