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March 26, 2017

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establish the identity:

cot(A-B)= cotAcotB+1/cotB-cotA

thanks for any help at all

  • trig - ,

    Is the final term
    1/(cotB-cotA) or
    (1/cotB)-cotA ??

    Is the numerator term (cotA cotB +1) or 1 ?

    When you write equations like that, we can't tell what you mean.

    I suggest you start with the identities for cos (A-B) and sin (A-B) and take the ratio of the two.

  • trig - ,

    cos(a+b)/sin(a+b)=
    cosacosb+sinasinb/sinacosb-cosasinb
    multiplying and dividing by sinasins then it becomes
    cotacotb+1/cotb-cota

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