Posted by **Amanda** on Tuesday, July 15, 2008 at 12:54am.

The line through (2,-3) and parallel to 2x+5y=3.

The line through (2,-3) and perpendicular to 2x+5y=3.

I just can't remember how to solve either of these kinds of problems and i can't find my notes on the subject.

- lines -
**drwls**, Tuesday, July 15, 2008 at 1:03am
The slope "m" of the first line must be -2/5. You get that by rewriting

2x + 5y = 3 as

y = -(2/5)x + 3/5

The slope "m" of the second line must be 5/2, because the product of the slopes of the two lines must be -1.

When you know the slope m and the point x1, y1 that the line goes through, the equation of the line can be written

(y - y1)/(x - x1) = m

## Answer this Question

## Related Questions

- Algebra 1 - 1.To solve the linear system below, which substitution of unkowns is...
- math - parallel and perpendicular lines Determine an equation of each of the ...
- Pre-Calculus - Hi! I have three questions that I need checked over just to make ...
- Pre- Algebra - Given an equation of a line, how do I find equations for lines ...
- algebra 1,urgent - the expression (4x^2-3x+1)-(x^3+2x+7) what is the coefficient...
- MAT221 - consider the line 8x-5y=-4 find the equation of the line that is ...
- Math -Quadratics Help! - I have a test tomorrow with a few sample questions that...
- Math - Quadratics & Analytical Geometry - I have a test tomorrow with a few ...
- Math- finding equation - Can someone explain to me how to find the equation pf ...
- Algebra II - Can you make sure my Algebra II work is correct? I've done the ...

More Related Questions