Posted by **brandy** on Monday, July 14, 2008 at 10:09pm.

hello, i don't quite understand how to do this type of problem:

1. find the exact value of sin (pi/3).

even more confusing is

2. find the exact value of csc^-1 (1).

i would appreciate any kind of help! thank you!

- trig/pre -calc -
**Anonymous**, Monday, July 14, 2008 at 10:54pm
I normally like to replace pi with 180.

So...

sin(pi/3)

= sin(180/3)

= sin(60)

What is sin(60)? sqrt(3)/2

As for csc^-1(1), I like to think of this as its inverse, 1/sin^-1(1). Where in the unit circle is sin=1? That is, where is y=1? 90 degrees

- trig/pre -calc -
**drwls**, Tuesday, July 15, 2008 at 12:34am
Since they seem to want angles to be expressed in radians, it might be better to give pi/2 as the answer to csc^-1(1) . 90 degrees is also correct, of course.

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