Posted by **Lewis** on Saturday, July 12, 2008 at 11:25am.

Hi,

Can anyone please check ....

If the values of n and m that have been used to construct the chiral vector equal ( n, m ) = ( 7,3 ).

n - m is 7 - 3 = 4

For a given (n,m) nanotube, if n − m is a multiple of 3, then the nanotube is metallic, otherwise the nanotube is a semiconductor. Thus all armchair (n=m) nanotubes are metallic, and nanotubes (5,0), (6,4), (9,1),

Is it right to assume that the above is a semi conducting nanotube rather than a metallic carbon nanotube ...

Thank you :-)

- Physics .. critique -
**drwls**, Saturday, July 12, 2008 at 1:13pm
Since n-m is not a multple of 3 for the nanotubes with chiral vectors (n,m) = (5,0), (6,4)and (9,1), they are all semiconductors.

## Answer This Question

## Related Questions

- Vector Table (physics) - I have to find the magnitude and direction of a ...
- Physics - partscoretotalsubmissions1--10/12--10/13--10/14--10/1----4--The tail ...
- Physics - The three vectors have magnitude a =3m, b= 4m and c=10m . On the x ...
- Computer Science (MATLAB) - Given a vector of values of zeros and ones such as [...
- Physics - The tail of a vector is fixed to the origin of an x, y axis system. ...
- calculus - State whether or not the following statements are true. Justify your ...
- Calculus - Dot Product - consider a rhombus ABCD a) find the resultant of vector...
- Physics/Math - In the vector sum A + B = C , vector A has a magnitude of 13.1 m ...
- Calc: PLEASE HELP! - How can this be proven! I have tried so many ways! PLEASE ...
- Vectors - Verify using an example that Vector a + (Vector b • Vector c) is not ...

More Related Questions