Wednesday

January 28, 2015

January 28, 2015

Posted by **C** on Thursday, July 10, 2008 at 7:40pm.

During the first part of a trip, a canoeist travels 63 miles at a certain speed. The canoeist travels 6 miles on the second part of the trip at a speed of 5 mph. slower. The total time for the trip is 5 hours.

1. What was the speed (Mph) for the first part of the trip?

2. What was the speed (Mph) for the second part of the trip?

- algebra -
**Quidditch**, Thursday, July 10, 2008 at 8:23pmlet x = speed of first part of trip in mph

let x-5 = speed of second part of trip in mph

5 hours = 63 miles/x + 6/(x-5)

Solve for x. If you solve a quadratic, ignore the answer which would cause the slower speed to be negative (non-real case).

**Answer this Question**

**Related Questions**

Algebra - Please HELP - During the first part of a trip a canoeist travels 49 ...

algebra 2 - During the first part of a trip a canoeist travels 26 miles at a ...

algebra - during the first part of a trip a canoeist travels 64 miles at a ...

Algebra - During the first part of a trip, a canoeist travels 57 miles at a ...

algebra - During the first part of a trip a canoeist travels 71 miles at a ...

algebra - During the first part of a trip, a canoeist travels 69 miles at a ...

Algebra - During the first part of a trip a canoeist travels 49 miles at a ...

ALGEBRA - DURING THE FIRST PART OF A TRIP, A CANOEIST TRAVELS 35 MILES AT A ...

Algebra - During the first part of a trip, a canoeist travels 98 miles at a ...

math - During the first part of a trip, a canoeist travels 93 miles at a certain...