Calculus
posted by Vanessa .
For the function f(x) = 1/x^2 find an expression for the slope of a tangent at the point where a = 1 using . Simplify the expression first before substitution.

using the limits formula....

point A
f(x) = 1/(x^2)
point B
f(x+deltaX) = 1/((x+deltaX)^2)
The slope of the line between these points is:
[f(x+deltaX)  f(x)]/[(x+deltaX  x]
The slope of the tangent is given when deltaX>0.
to get you started...
[(1/(x+deltaX)^2)  1/x^2]/[x+deltaX  x]
Get rid of the fractions in the numerator and reduce the fraction as much as possible. Then take the limit as deltaX>0.