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Calculus

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For the function f(x) = 1/x^2 find an expression for the slope of a tangent at the point where a = 1 using . Simplify the expression first before substitution.

  • Calculus - ,

    using the limits formula....

  • Calculus - ,

    point A
    f(x) = 1/(x^2)

    point B
    f(x+deltaX) = 1/((x+deltaX)^2)

    The slope of the line between these points is:

    [f(x+deltaX) - f(x)]/[(x+deltaX - x]

    The slope of the tangent is given when deltaX->0.

    to get you started...

    [(1/(x+deltaX)^2) - 1/x^2]/[x+deltaX - x]
    Get rid of the fractions in the numerator and reduce the fraction as much as possible. Then take the limit as deltaX->0.

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