Posted by **Vanessa** on Thursday, July 10, 2008 at 1:23pm.

For the function f(x) = 1/x^2 find an expression for the slope of a tangent at the point where a = 1 using . Simplify the expression first before substitution.

- Calculus -
**Vanessa**, Thursday, July 10, 2008 at 1:52pm
using the limits formula....

- Calculus -
**Quidditch**, Thursday, July 10, 2008 at 7:50pm
point A

f(x) = 1/(x^2)

point B

f(x+deltaX) = 1/((x+deltaX)^2)

The slope of the line between these points is:

[f(x+deltaX) - f(x)]/[(x+deltaX - x]

The slope of the tangent is given when deltaX->0.

to get you started...

[(1/(x+deltaX)^2) - 1/x^2]/[x+deltaX - x]

Get rid of the fractions in the numerator and reduce the fraction as much as possible. Then take the limit as deltaX->0.

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