Person 1 was walking down a path one day when Person2 appeared in front of it at exactly 8:06 AM.

The next day, Person 1 was walking down the same path, and Person 2 appeared in front of it at 6:03 PM.

The next day, the same thing happened at 11:05 AM.

The next three days were at 3:09 PM, 5:05 AM, and 4:01 AM.

How do I solve this?

What are you being asked to solve? Averge time of encounter? Standard deviation?

What is the time that they will meet on the 7th day?

Someone doing Lenny's Conundrum?! :)

To solve this, we need to find a pattern in the times when Person 2 appears in front of Person 1 on different days.

First, let's convert the given times to a 24-hour format for easier comparison:

8:06 AM = 08:06
6:03 PM = 18:03
11:05 AM = 11:05
3:09 PM = 15:09
5:05 AM = 05:05
4:01 AM = 04:01

Now, let's observe these times:

08:06
18:03
11:05
15:09
05:05
04:01

Seeing the times written in this format, we can notice that the first two digits (hour) do not form a pattern, but the last two digits (minutes) seem to follow a pattern.

To identify the pattern, let's focus on the last two digits of the minutes:

06
03
05
09
05
01

We can observe that these numbers are all in increasing order until reaching the maximum of 09, and then they repeat the pattern from the beginning.

So, the pattern for the minutes is: 06, 03, 05, 09, 05, 01.

Now, looking at the original question, we see that the days and times given match this pattern in a specific order. The first time appears in the morning, then in the evening, followed by morning, afternoon, morning, and finally, early morning.

Therefore, based on the given information, the pattern suggests that the next time Person 2 will appear in front of Person 1 will be in the evening, and the minutes will follow the pattern, starting with 07.

To summarize, the next time Person 2 will appear in front of Person 1 is predicted to be at 7:07 PM.