Posted by Derek on Wednesday, July 9, 2008 at 8:07pm.
None of the normals are scalar multiples of each other, so none of your planes are parallel
If we multiply the third equation by 3 we get 3z in all three equations.
#2 - #1 gave me x+11y = 4
the new #3 - #2 gave me 6x - 18y = 3
solving those two equations in x and y gave me x = 5/4 and y = 1/4
subbing that back into one of the originals I got z = -15/4
So your 3 planes intersect in a point, namely (5/4,1/4,-15/4)
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