Posted by Derek on Wednesday, July 9, 2008 at 8:07pm.
Use normal vectors to determine the intersection, if any, for each of the following groups of three planes. Give a geometric interpretation in each case and the number of solutions for the corresponding linear system of equations. If the planes intersect in a line, determine a vector equation of the line. If the planes intersect in a point, determine the coordinates of the point.
2x − 5y + 3z = −10
3x + 6y + 3z = −6
3x − 4y + z = −1

Calc.  Reiny, Wednesday, July 9, 2008 at 9:57pm
None of the normals are scalar multiples of each other, so none of your planes are parallel
If we multiply the third equation by 3 we get 3z in all three equations.
#2  #1 gave me x+11y = 4
the new #3  #2 gave me 6x  18y = 3
solving those two equations in x and y gave me x = 5/4 and y = 1/4
subbing that back into one of the originals I got z = 15/4
So your 3 planes intersect in a point, namely (5/4,1/4,15/4)