Posted by Elisa on Monday, July 7, 2008 at 5:14pm.
the change of momentum of the arrow will be the same as the change of momentum of the target
initial target momentum = 0.300 * 2.35 = .705 kg m/s
final target momentum = 0
so the arrow momentum will be reduced by .705 kg m/s
final arrow momentum = .0225*41 - .705
= .2175 kg m/s
final arrow speed = .2175/.0225 = 9.67 m/s
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