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An archer shoots an arrow toward a 300 g target that is sliding in her direction at a speed of 2.35 m/s on a smooth, slippery surface. The 22.5 g arrow is shot with a speed of 41.0 m/s and passes through the target, which is stopped by the impact. What is the speed of the arrow after passing through the target?

  • physics -

    the change of momentum of the arrow will be the same as the change of momentum of the target
    initial target momentum = 0.300 * 2.35 = .705 kg m/s
    final target momentum = 0
    so the arrow momentum will be reduced by .705 kg m/s
    final arrow momentum = .0225*41 - .705
    = .2175 kg m/s
    final arrow speed = .2175/.0225 = 9.67 m/s

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