posted by Elisa on .
An archer shoots an arrow toward a 300 g target that is sliding in her direction at a speed of 2.35 m/s on a smooth, slippery surface. The 22.5 g arrow is shot with a speed of 41.0 m/s and passes through the target, which is stopped by the impact. What is the speed of the arrow after passing through the target?
the change of momentum of the arrow will be the same as the change of momentum of the target
initial target momentum = 0.300 * 2.35 = .705 kg m/s
final target momentum = 0
so the arrow momentum will be reduced by .705 kg m/s
final arrow momentum = .0225*41 - .705
= .2175 kg m/s
final arrow speed = .2175/.0225 = 9.67 m/s