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November 23, 2014

November 23, 2014

Posted by **Elisa** on Sunday, July 6, 2008 at 11:01pm.

x component: N

y component: N

2. A 7.0 g bullet is fired into a 1.5 kg ballistic pendulum. The bullet emerges from the block with a speed of 200 m/s, and the block rises to a maximum height of 11 cm. Find the initial speed of the bullet.

- physics -
**drwls**, Monday, July 7, 2008 at 7:49am1. The velocity component normal to the wall (which I will call the x direction) changes from 10.0 sin 60 to -10.0 sin 60. That is a velocity component change of 17.32 m/s. Multiply that by the mass for the momentum change in that direction. Dividing by the contact time gives you the x xomponent of the force.

The velocity component in the y direction does not change, so there is no applied force in that direction.

2. Get the velocity V of the block right after it is hit by applying conservation of energy to the rise of the ballistic pendulum afterwards.

V = sqrt (2gH),

here H = 0.11 m and g = 9.8 m/s^2.

Let v1 and v2 be the velocity of the bullet before and after passing through the block. Apply conservation of linear momentum to that impact

m (v1 - v2) = M V

M is the mass of the block amd m is the mass of the bullet.

Solve for v1

- physics -
**Julia**, Tuesday, November 1, 2011 at 3:02pmA spy in a speed boat is being chased down a river by government officials in a faster craft. Just as the officials' boat pulls up next to the spy's boat, both boats reach the edge of a 4.8 m waterfall. The spy's speed is 16 m/s and the officials; speed is 26 m/s. How far apart will the two vessels be when they land below the waterfall? The acceleration of gravity is 9.81 m/s . Answer in units of m

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